Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 163226 by nurtani last updated on 05/Jan/22

Commented by Rasheed.Sindhi last updated on 06/Jan/22

Sir mr W,why have you deleted your  answer?

$$\boldsymbol{\mathrm{Sir}}\:\boldsymbol{\mathrm{mr}}\:\boldsymbol{\mathrm{W}},{why}\:{have}\:{you}\:{deleted}\:{your} \\ $$$${answer}? \\ $$

Commented by mr W last updated on 06/Jan/22

sometimes i delete my answer when  i see that there exists already the   same or similar answer from other  people.

$${sometimes}\:{i}\:{delete}\:{my}\:{answer}\:{when} \\ $$$${i}\:{see}\:{that}\:{there}\:{exists}\:{already}\:{the}\: \\ $$$${same}\:{or}\:{similar}\:{answer}\:{from}\:{other} \\ $$$${people}. \\ $$

Commented by Rasheed.Sindhi last updated on 06/Jan/22

Understood sir!

$${Understood}\:\boldsymbol{{sir}}! \\ $$

Answered by cortano1 last updated on 05/Jan/22

  2^(5x−1)  . 3^(4x+1)  .7^(3x+3)  = 2^(3x−6)  .3^(2x−4)  .7^(x−2)    ⇒x=−(5/2)

$$\:\:\mathrm{2}^{\mathrm{5}{x}−\mathrm{1}} \:.\:\mathrm{3}^{\mathrm{4}{x}+\mathrm{1}} \:.\mathrm{7}^{\mathrm{3}{x}+\mathrm{3}} \:=\:\mathrm{2}^{\mathrm{3}{x}−\mathrm{6}} \:.\mathrm{3}^{\mathrm{2}{x}−\mathrm{4}} \:.\mathrm{7}^{{x}−\mathrm{2}} \\ $$$$\:\Rightarrow{x}=−\frac{\mathrm{5}}{\mathrm{2}} \\ $$

Answered by Rasheed.Sindhi last updated on 05/Jan/22

2^(5x−1) .3^(4x+1) .7^(3x+3) =(2^3 .3^2 .7)^(x−2)          =2^(3x−6) .3^(2x−4) .7^(x−2))   2^(5x−1−3x+6) .3^(4x+1−2x+4) .7^(3x+3−x+2) =1  2^(2x+5) .3^(2x+5) .7^(2x+5) =1  (2.3.7)^(2x+5) =(2.3.7)^0   2x+5=0  x=−(5/2)

$$\mathrm{2}^{\mathrm{5}{x}−\mathrm{1}} .\mathrm{3}^{\mathrm{4}{x}+\mathrm{1}} .\mathrm{7}^{\mathrm{3}{x}+\mathrm{3}} =\left(\mathrm{2}^{\mathrm{3}} .\mathrm{3}^{\mathrm{2}} .\mathrm{7}\right)^{{x}−\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:=\mathrm{2}^{\mathrm{3}{x}−\mathrm{6}} .\mathrm{3}^{\mathrm{2}{x}−\mathrm{4}} .\mathrm{7}^{\left.{x}−\mathrm{2}\right)} \\ $$$$\mathrm{2}^{\mathrm{5}{x}−\mathrm{1}−\mathrm{3}{x}+\mathrm{6}} .\mathrm{3}^{\mathrm{4}{x}+\mathrm{1}−\mathrm{2}{x}+\mathrm{4}} .\mathrm{7}^{\mathrm{3}{x}+\mathrm{3}−{x}+\mathrm{2}} =\mathrm{1} \\ $$$$\mathrm{2}^{\mathrm{2}{x}+\mathrm{5}} .\mathrm{3}^{\mathrm{2}{x}+\mathrm{5}} .\mathrm{7}^{\mathrm{2}{x}+\mathrm{5}} =\mathrm{1} \\ $$$$\left(\mathrm{2}.\mathrm{3}.\mathrm{7}\right)^{\mathrm{2}{x}+\mathrm{5}} =\left(\mathrm{2}.\mathrm{3}.\mathrm{7}\right)^{\mathrm{0}} \\ $$$$\mathrm{2}{x}+\mathrm{5}=\mathrm{0} \\ $$$${x}=−\frac{\mathrm{5}}{\mathrm{2}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com