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Question Number 163340 by mathlove last updated on 06/Jan/22

Answered by Rasheed.Sindhi last updated on 06/Jan/22

$$\frac{a^2-b^2}{a+b}=a-b$$$$=[1+\frac{1}{1+\frac{1}{100}}-(1-\frac{1}{1+\frac{1}{100}})]$$$$=[1+\frac{1}{1+\frac{1}{100}}-1+\frac{1}{1+\frac{1}{100}}]$$$$2\left(\frac{1}{1+\frac{1}{100}}\right)=2\times \frac{100}{101}=\frac{200}{101}\left(b\right)✓$$

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