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Question Number 163346 by MathsFan last updated on 06/Jan/22

$$howdoicalculatefor\frac{1}{2}!$$

Commented by Ar Brandon last updated on 06/Jan/22

$$\mathrm{\Gamma }(x+1)=x\mathrm{\Gamma }\left(x\right)=x(x-1)\mathrm{\Gamma }(x-1)...\mathrm{\Gamma }\left(1\right)=x!$$$$\mathrm{\Gamma }\left(\frac{1}{2}\right)=\sqrt{\pi },\mathrm{\Gamma }\left(1\right)=1$$$$\left(\frac{1}{2}\right)!=\mathrm{\Gamma }(\frac{1}{2}+1)=\frac{1}{2}\mathrm{\Gamma }\left(\frac{1}{2}\right)=\frac{\sqrt{\pi }}{2}$$

Commented by MathsFan last updated on 06/Jan/22

$$merci$$

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