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Question Number 163573 by Zaynal last updated on 08/Jan/22

Commented by MJS_new last updated on 08/Jan/22

=((sec^(−1) )/(3cosec^(−1) ))∫(dx/x^2 )  or rewrite it properly

$$=\frac{\mathrm{sec}^{−\mathrm{1}} }{\mathrm{3cosec}^{−\mathrm{1}} }\int\frac{{dx}}{{x}^{\mathrm{2}} } \\ $$$$\mathrm{or}\:\mathrm{rewrite}\:\mathrm{it}\:\mathrm{properly} \\ $$

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