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Question Number 163611 by Ramjiane last updated on 08/Jan/22

Answered by ajfour last updated on 08/Jan/22

(1)  d=(h/(cot 25°−cot 50°))  (2) You jus cant do without.

$$\left(\mathrm{1}\right)\:\:{d}=\frac{{h}}{\mathrm{cot}\:\mathrm{25}°−\mathrm{cot}\:\mathrm{50}°} \\ $$$$\left(\mathrm{2}\right)\:{You}\:{jus}\:{cant}\:{do}\:{without}. \\ $$

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