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Question Number 163782 by bekzodjumayev last updated on 10/Jan/22
Commented by bekzodjumayev last updated on 10/Jan/22
Pleasehelp
Answered by Ar Brandon last updated on 10/Jan/22
L=limx→−1xn−nx+(1−n)(x+1)2=limt→0(t−1)n−n(t−1)+(1−n)t2,nodd⇒(−1)n=−1=limt→0(−1)n(1−nt−n(n−1)2t2)−nt+n+1−nt2=limt→0−1+nt+n(n−1)2t2−nt+1t2=limt→0n(n−1)t22t2=n(n−1)2
Commented by bekzodjumayev last updated on 11/Jan/22
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