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Question Number 163789 by amin96 last updated on 10/Jan/22
∫01arccotgh(x)1−x2dx=?byM.A
Commented by MJS_new last updated on 10/Jan/22
tanhx=e2x−1e2x+1cothx=e2x+1e2x−1arcothx=12lnx+1x−112∫lnx+1x−11−x2dx=18(lnx+1x−1)2+C⇒∫10arcothx1−x2dxdoesn′tconverge
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