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Question Number 163861 by mathlove last updated on 11/Jan/22

Answered by Ar Brandon last updated on 11/Jan/22

$$x=\sqrt{5}+\frac{1}{x}\Rightarrow x=\frac{\sqrt{5}\pm \sqrt{9}}{2}=\frac{\sqrt{5}+3}{2}(x>0,\sqrt{5}-3<0)$$

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