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Question Number 163888 by zakirullah last updated on 11/Jan/22
prove∫1−x21−x2dx=∫1−x2dx
Commented by mr W last updated on 12/Jan/22
a2a=aisobvious.
Answered by essojean last updated on 11/Jan/22
∫1−x21−x2dx=∫(1−x2)×(1−x2)−12dx=∫(1−x2)1−12dx=∫(1−x2)12dx=∫1−x2dx.....
Commented by zakirullah last updated on 12/Jan/22
nicesolutionDearSirAboundleofthanks.
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