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Question Number 163926 by cortano1 last updated on 12/Jan/22

{: ((sin θ=1−sin^2 θ)),((csc^2 θ−tan^2 θ =? )) }

sinθ=1−sin2θcsc2θ−tan2θ=?}

Answered by MJS_new last updated on 12/Jan/22

s^2 =1−s ⇒ (1/s^2 )−(s^2 /(1−s^2 ))=(1/(1−s))−((1−s)/s)=((s−(1−s)^2 )/(s−s^2 ))=((4s−2)/(2s−1))=2

s2=1−s⇒1s2−s21−s2=11−s−1−ss=s−(1−s)2s−s2=4s−22s−1=2

Answered by cortano1 last updated on 12/Jan/22

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