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Question Number 163968 by mathls last updated on 12/Jan/22

(−2^2 )^3 =?

$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =? \\ $$

Answered by cortano1 last updated on 12/Jan/22

(−2^2 )=−4  (−2^2 )^3 =(−4)^3 =−64

$$\left(−\mathrm{2}^{\mathrm{2}} \right)=−\mathrm{4} \\ $$$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =\left(−\mathrm{4}\right)^{\mathrm{3}} =−\mathrm{64} \\ $$

Commented by mathls last updated on 12/Jan/22

(−2^2 )^3 =(−2)^6 =64   isn′t correct?

$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =\left(−\mathrm{2}\right)^{\mathrm{6}} =\mathrm{64}\:\:\:{isn}'{t}\:{correct}? \\ $$

Commented by cortano1 last updated on 12/Jan/22

no

$${no} \\ $$

Commented by cortano1 last updated on 12/Jan/22

(−2^2 )^3 =(−2^2 )×(−2^2 )×(−2^2 )   = (−4)×(−4)×(−4)=−64

$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =\left(−\mathrm{2}^{\mathrm{2}} \right)×\left(−\mathrm{2}^{\mathrm{2}} \right)×\left(−\mathrm{2}^{\mathrm{2}} \right) \\ $$$$\:=\:\left(−\mathrm{4}\right)×\left(−\mathrm{4}\right)×\left(−\mathrm{4}\right)=−\mathrm{64} \\ $$

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