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Question Number 163978 by Eric002 last updated on 12/Jan/22

Commented by Eric002 last updated on 12/Jan/22

$a c o n t i n u o u s t i m e s i g n a l s h o w n i n t h e$ $f i g . d e t e r m i n e t h e f o l l o w i n g v e r s i o n o f$ $t h e s i g n a l$ $a) x (t + 2)$ $b) - (x) t$ $c) x (3 - 2 t)$ $d) \frac{x (t) + x (- t)}{2}$
Commented by JDamian last updated on 12/Jan/22
A "continuous" time signal in the popular meaning I guess, because that x(t) for t=1 is not continuous in the mathematical meaning
Commented by Eric002 last updated on 13/Jan/22

$t h a n k y o u s i r f o r y o u r c o m m e n t$ $i n c o m m u n i c a t i o n s i g n a l s$ $c o u n t i n u o u s t i m e s i g n a l s$ $m e a n s t h e v a l u e o f (t) i s c o u n t i n u e$ $i n x (t) n o t d i s c r e t e p o i n t s s o c o u n t i u e$ $t i m e s i g n a l s n e e d n o t t o b e c o u n t i n u o u e s$ $m a t h m a t i c a l y$
Commented by Eric002 last updated on 13/Jan/22

Commented by Eric002 last updated on 13/Jan/22

$f o r e x a m p l e a i s c o u n t i n u o u s t i m e s i g n a l$ $a n d b i s d i s c r e t e t i m e s i g n a l$
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