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Question Number 163993 by mathls last updated on 12/Jan/22

Commented by mathls last updated on 12/Jan/22

$p l e a s e h e l p$
Commented by mr W last updated on 12/Jan/22

$r e l a t i v e a c c e l e r a t i o n = 0$ $r e l a t i v e s p e e d = 25 m / s$ $r e l a t i v e p o s i t i o n a t b e g i n n i n g = 100 m$ $25 t = 100 \Rightarrow t = 4 s$ $i . e . a f t e r 4 s e c o n d s t h e d i s t a n c e$ $b e t w e e n b o t h i s z e r o .$
Commented by mathls last updated on 13/Jan/22

$w h a t i s t h e p r a c t i c e ?$
Commented by mr W last updated on 13/Jan/22

$m y p r a c t i c e i s w h a t i w r o t e .$ $r e l a t i v e l y b o t h o b j e c t s m o v e w i t h a$ $r e l a t i v e s p e e d 25 m / s t o w a r d s e a c h$ $o t h e r . s i n c e t h e y h a v e a d i s t a n c e o f$ $100 m a t b e g i n n i n g, t h e r e f o r e a f t e r$ $4 s e c o n d s, t h e i r d i s t a n c e i s z e r o .$
Commented by mr W last updated on 13/Jan/22

$m a y b e y o u w o u l d d o a s f o l l o w i n g .$ $p o s i t i o n o f o b j e c t 1 :$ $y = 25 t - \frac{{g t}^{2}}{2}$ $p o s i t i o n o f o b j e c t 2 :$ $y = 100 - \frac{{g t}^{2}}{2}$ $w h e n b o t h o b j e c t s p a s s s i d e b y s i d e,$ $25 t - \frac{{g t}^{2}}{2} = 100 - \frac{{g t}^{2}}{2}$ $\Rightarrow 25 t = 100$ $\Rightarrow t = \frac{100}{25} = 4 s e c o n d s$
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