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Question Number 164039 by ArielVyny last updated on 13/Jan/22

consider f function Df=[0,1]  f(0)=f(1) c∈[0,(1/2)] show that f(c)=f(c+(1/2))

considerffunctionDf=[0,1]f(0)=f(1)c[0,12]showthatf(c)=f(c+12)

Answered by Ar Brandon last updated on 13/Jan/22

f(0)=f(1)  f(c+0)=f(c+1) , since f < 1-periodic  f(c)=f((c+(1/2))+(1/2))=f(c+(1/2))  Hence f(c)=f(c+(1/2))

f(0)=f(1)f(c+0)=f(c+1),sincef<1periodicf(c)=f((c+12)+12)=f(c+12)Hencef(c)=f(c+12)

Commented by Ar Brandon last updated on 13/Jan/22

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