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Question Number 164121 by mkam last updated on 14/Jan/22

if w = f(x,y) and x = r cosθ , y = rsinθ    then prove that w_(rr)  + w_(θθ)  = 0?

$${if}\:{w}\:=\:{f}\left({x},{y}\right)\:{and}\:{x}\:=\:{r}\:{cos}\theta\:,\:{y}\:=\:{rsin}\theta \\ $$$$ \\ $$$${then}\:{prove}\:{that}\:{w}_{{rr}} \:+\:{w}_{\theta\theta} \:=\:\mathrm{0}? \\ $$

Commented by mkam last updated on 14/Jan/22

????

$$???? \\ $$

Commented by mkam last updated on 15/Jan/22

???

$$??? \\ $$

Commented by mr W last updated on 15/Jan/22

you cant prove!  it′s false!

$${you}\:{cant}\:{prove}! \\ $$$${it}'{s}\:{false}! \\ $$

Answered by mr W last updated on 15/Jan/22

w_r =f_x cos θ+f_y sin θ  w_(rr) =f_(xx) cos^2  θ+f_(xy) cos θ sin θ+f_(yx) sin θ cos θ+f_(yy) sin^2  θ  w_θ =−f_x r sin θ+f_y r cos θ  w_(θθ) =−f_x r cos θ−r sin θ (−f_(xx) r sin θ+f_(xy) r cos θ)−f_y r sin θ+r cos θ (−f_(xy) r sin θ+f_(yy) r cos θ)  w_(θθ) =−f_x r cos θ+f_(xx) r^2  sin^2  θ−f_(xy) r^2  sin θ cos θ−f_y r sin θ−f_(xy) r^2  sin θ cos θ+f_(yy) r^2  cos^2  θ  w_(θθ) =−f_x r cos θ−f_y r sin θ+f_(xx) r^2  sin^2  θ+f_(yy) r^2  cos^2  θ−2f_(xy) r^2  sin θ cos θ  w_(rr) +w_(θθ) ≠0

$${w}_{{r}} ={f}_{{x}} \mathrm{cos}\:\theta+{f}_{{y}} \mathrm{sin}\:\theta \\ $$$${w}_{{rr}} ={f}_{{xx}} \mathrm{cos}^{\mathrm{2}} \:\theta+{f}_{{xy}} \mathrm{cos}\:\theta\:\mathrm{sin}\:\theta+{f}_{{yx}} \mathrm{sin}\:\theta\:\mathrm{cos}\:\theta+{f}_{{yy}} \mathrm{sin}^{\mathrm{2}} \:\theta \\ $$$${w}_{\theta} =−{f}_{{x}} {r}\:\mathrm{sin}\:\theta+{f}_{{y}} {r}\:\mathrm{cos}\:\theta \\ $$$${w}_{\theta\theta} =−{f}_{{x}} {r}\:\mathrm{cos}\:\theta−{r}\:\mathrm{sin}\:\theta\:\left(−{f}_{{xx}} {r}\:\mathrm{sin}\:\theta+{f}_{{xy}} {r}\:\mathrm{cos}\:\theta\right)−{f}_{{y}} {r}\:\mathrm{sin}\:\theta+{r}\:\mathrm{cos}\:\theta\:\left(−{f}_{{xy}} {r}\:\mathrm{sin}\:\theta+{f}_{{yy}} {r}\:\mathrm{cos}\:\theta\right) \\ $$$${w}_{\theta\theta} =−{f}_{{x}} {r}\:\mathrm{cos}\:\theta+{f}_{{xx}} {r}^{\mathrm{2}} \:\mathrm{sin}^{\mathrm{2}} \:\theta−{f}_{{xy}} {r}^{\mathrm{2}} \:\mathrm{sin}\:\theta\:\mathrm{cos}\:\theta−{f}_{{y}} {r}\:\mathrm{sin}\:\theta−{f}_{{xy}} {r}^{\mathrm{2}} \:\mathrm{sin}\:\theta\:\mathrm{cos}\:\theta+{f}_{{yy}} {r}^{\mathrm{2}} \:\mathrm{cos}^{\mathrm{2}} \:\theta \\ $$$${w}_{\theta\theta} =−{f}_{{x}} {r}\:\mathrm{cos}\:\theta−{f}_{{y}} {r}\:\mathrm{sin}\:\theta+{f}_{{xx}} {r}^{\mathrm{2}} \:\mathrm{sin}^{\mathrm{2}} \:\theta+{f}_{{yy}} {r}^{\mathrm{2}} \:\mathrm{cos}^{\mathrm{2}} \:\theta−\mathrm{2}{f}_{{xy}} {r}^{\mathrm{2}} \:\mathrm{sin}\:\theta\:\mathrm{cos}\:\theta \\ $$$${w}_{{rr}} +{w}_{\theta\theta} \neq\mathrm{0} \\ $$

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