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Question Number 164530 by hoochhoch last updated on 18/Jan/22

Commented by Rasheed.Sindhi last updated on 18/Jan/22

sinα=−((12)/3)=−4⇒α∉R in Q#1

You can't use 'macro parameter character #' in math mode

Answered by Rasheed.Sindhi last updated on 18/Jan/22

sinα=(3/5) ;((cotα+tanα  )/(cotα−tanα))=?  ((cotα+tanα  )/(cotα−tanα))=((((cosα )/(sinα ))+((sinα )/(cosα )))/(((cosα )/(sinα ))−((sinα )/(cosα ))))  =((cos^2 α+sin^2 α  )/(cos^2 α−sin^2 α))=(1/(1−2sin^2 α ))  =(1/(1−2((3/5))^2 ))=(1/((25−18)/(25)))=((25)/7)

sinα=35;cotα+tanαcotαtanα=?cotα+tanαcotαtanα=cosαsinα+sinαcosαcosαsinαsinαcosα=cos2α+sin2αcos2αsin2α=112sin2α=112(35)2=1251825=257

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