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Question Number 164758 by mathlove last updated on 21/Jan/22

$$tan22=\frac{2}{5}$$$$\frac{sin112+sin202}{cos(-68)}=?$$

Answered by Rasheed.Sindhi last updated on 21/Jan/22

$$\frac{\sin 112+\sin 202}{\cos (-68)}$$$$=\frac{\sin (90+22)+\sin (180+22)}{\cos (22-90)}$$$$=\frac{\cos 22-\sin 22}{\sin 22}$$$$=\frac{\cos 22}{\sin 22}-1$$$$=\frac{1}{\tan 22}-1$$$$=\frac{5}{2}-1=\frac{3}{2}$$

Commented by mathlove last updated on 21/Jan/22

$$thanks$$

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