tan193=k cos167=?


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Question Number 188725 by 073 last updated on 06/Mar/23

$\tan 193 = k$ $\cos 167 = ?$
	Answered by BaliramKumar last updated on 06/Mar/23

	$t a n 193 = k$ $t a n (180 + 13) = t a n 13 = k$ $c o s 167 = c o s (180 - 13) = - c o s 13$ $- c o s 13 = \frac{- 1}{s e c 13} = \frac{- 1}{\sqrt{1 + {t a n}^{2} 13}} = \frac{- 1}{\sqrt{1 + k^{2}}}$
	Commented by 073 last updated on 06/Mar/23

	$nice solution$
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