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Question Number 164788 by cortano1 last updated on 22/Jan/22

Answered by leonhard77 last updated on 22/Jan/22

$$\Rightarrow \tan 30°=\frac{\tan 28°+\tan 2°}{1-\tan 28.\tan 2°°}$$$$\Rightarrow \frac{1}{\sqrt{3}}=\frac{\tan 28°+\tan 2°}{1-\tan 28°.\tan 2°}$$$$1-\tan 28°.\tan 2°=\sqrt{3}(\tan 28°+\tan 2°)$$$$$$$$\tan 28°=\frac{\tan 26°+\tan 2°}{1-\tan 26°.\tan 2°}$$$$=\frac{\frac{\sqrt{1-x^2}}{x}+\tan 2°}{1-\frac{\sqrt{1-x^2}}{x}\tan 2°}$$$$=\frac{\sqrt{1-x^2}+x\tan 2°}{x-\sqrt{1-x^2}\tan 2°}$$

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