Question Number 164856 by Zaynal last updated on 22/Jan/22
$$\:\:\:\:\boldsymbol{\mathrm{Let}}\:\boldsymbol{{a}},\boldsymbol{{b}},\boldsymbol{{c}}\:>\mathrm{0}; \\ $$ $$\:\:\:\:\mathrm{42}\boldsymbol{{abc}}\:+\:\mathrm{4}\boldsymbol{{bca}}\:+\mathrm{1}\boldsymbol{{cab}}\:\leqslant\:\mathrm{24} \\ $$ $$\:\:\:\:\mathrm{T}\boldsymbol{\mathrm{hen}}\:\frac{\mathrm{1}}{\boldsymbol{\mathrm{ab}}}\:+\:\frac{\mathrm{2}}{\boldsymbol{\mathrm{bc}}}\:+\:\frac{\mathrm{3}}{\boldsymbol{\mathrm{ca}}}\:=\:?? \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:^{\left\{{Z}.\mathrm{A}\right\}} \\ $$
Commented byMJS_new last updated on 24/Jan/22
$${abc}={bca}={cab} \\ $$ $$\mathrm{anyway}\:\mathrm{you}\:\mathrm{cannot}\:\mathrm{solve}\:\mathrm{this}\:\mathrm{equation}\:\mathrm{with} \\ $$ $$\mathrm{only}\:{one}\:\mathrm{inequation}\:\mathrm{given} \\ $$