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Question Number 164874 by cortano1 last updated on 22/Jan/22

Answered by mahdipoor last updated on 22/Jan/22

get x+(√(x^2 +1))=t ⇒ x^2 +1=t^2 +x^2 −2xt ⇒ ((t^2 −1)/(2t))=x f(t)=(x/(x+1))=(((t^2 −1)/(2t))/((t^2 +2t−1)/(2t)))=((t^2 −1)/(t^2 +2t−1))

getx+x2+1=t⇒x2+1=t2+x2−2xt⇒t2−12t=xf(t)=xx+1=t2−12tt2+2t−12t=t2−1t2+2t−1

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