Question and Answers Forum

All Questions      Topic List

Coordinate Geometry Questions

Previous in All Question      Next in All Question      

Previous in Coordinate Geometry      Next in Coordinate Geometry      

Question Number 165024 by cortano1 last updated on 25/Jan/22

Commented by cortano1 last updated on 25/Jan/22

$$finda.$$$$\left(A\right)2\sqrt{46}\left(C\right)12$$$$\left(B\right)2\sqrt{42}\left(D\right)2\sqrt{39}$$

Commented by som(math1967) last updated on 25/Jan/22

$$isadiametersir?$$

Commented by cortano1 last updated on 25/Jan/22

$$nosir$$

Commented by mr W last updated on 25/Jan/22

$$ifaisnotthediameter,whatisit$$$$then?$$

Commented by cortano1 last updated on 25/Jan/22

Commented by som(math1967) last updated on 25/Jan/22

$$a=2\sqrt{46}?$$

Commented by cortano1 last updated on 25/Jan/22

$$howsir?$$

Answered by mr W last updated on 25/Jan/22

Commented by mr W last updated on 25/Jan/22

$$h_1=\sqrt{R^2-7^2}$$$$h_2=\sqrt{R^2-5^2}$$$$\sqrt{R^2-7^2}+\sqrt{R^2-5^2}=6$$$$\sqrt{R^2-7^2}=6-\sqrt{R^2-5^2}$$$$6^2+7^2-5^2=2\times 6\sqrt{R^2-5^2}$$$$R^2=5^2+{\left(\frac{6^2+7^2-5^2}{2\times 6}\right)}^2=50$$$$h_1=\sqrt{50-7^2}=1$$$${\left(\frac{a}{2}\right)}^2=R^2-{(3-h_1)}^2=50-2^2=46$$$$\Rightarrow a=2\sqrt{46}$$

Commented by Tawa11 last updated on 25/Jan/22

$$\mathrm{Great}\mathrm{sir}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com