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Question Number 165068 by cortano1 last updated on 25/Jan/22

Commented by bobhans last updated on 25/Jan/22

$$\Rightarrow {\mathrm{x}}^{\log {}_{81}\left(243\right)}-2\mathrm{x}={(\mathrm{x}+2)}^{\log {}_{16}\left(2\right)}-8$$$$\Rightarrow {\mathrm{x}}^{\frac{5}{4}}-2\mathrm{x}={(\mathrm{x}+2)}^{\frac{1}{4}}-8$$

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