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Question Number 165153 by mathlove last updated on 26/Jan/22
f(x)=3e2xf−1(x)=?
Answered by mahdipoor last updated on 26/Jan/22
⇒x=3e2y⇒12lnx3=y=f−1(x)
Answered by MathsFan last updated on 27/Jan/22
lety=3e2xx=3e2y→logx=2ylog3e→2y=log3ex→y=log3ex2f−1(x)=log3ex2
Answered by alephzero last updated on 28/Jan/22
f(x)=3e2xf−1(x)=?x=3e2y⇒x3=e2y⇒lnx3=2y⇒lnx32=lnx−ln32=y⇒f−1(x)=lnx−ln32
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