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Question Number 165209 by HongKing last updated on 27/Jan/22

$$\mathrm{Find}:\underset{\mathbf{n}=1}{\sum ^{\mathbf{k}}}\frac{{\mathrm{n}}^2{\sin }^2\frac{\mathrm{n}\pi }{2}}{{\mathrm{n}}^4{\pi }^4+{\mathrm{n}}^2{\pi }^2\mathrm{a}+\mathrm{b}}=?$$

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