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Question Number 165243 by Zaynal last updated on 28/Jan/22

$$\lfloor \mathbf{Find}\mathbf{the}\mathbf{value}\mathbf{of}\mathit{x}???\rfloor$$$$\lfloor 5\mathit{x}+\frac{5\mathit{x}}{{(5+5)}^5}\times (-5\mathit{x})\mathbf{÷}555\mathit{x}-55\mathit{x}\times \frac{5\mathbf{÷}5}{5}+\mathit{x}=555555555555555\rfloor$$$${}^{\mathrm{proof}:\mathrm{z}.\mathrm{a}}$$

Answered by alephzero last updated on 28/Jan/22

$$5x+\frac{5x}{{(5+5)}^5}\times (-5x)\mathbf{÷}555x-55x\times$$$$\times \frac{5/5}{5}+x=55555555555555$$$$5x-\frac{\cancel{10}{x}^{\cancel{2}}}{\cancel{10}\times {10}^4}\times \frac{1}{555\cancel{x}}-\cancel{55}x\times \frac{1}{\cancel{5}}+x=$$$$=5x-\frac{x}{{10}^4\times 555}-11x+x=$$$$=5x-\frac{x}{{10}^4\times 555}-10x=$$$$=-5x-\frac{x}{5550000}=555555555555555$$$$-\frac{27750001x}{5550000}=555555555555555$$$$\Rightarrow x=-\frac{5550000\times 555555555555555}{27750001}$$

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