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Question Number 165291 by HongKing last updated on 28/Jan/22

Answered by mahdipoor last updated on 29/Jan/22

$$\frac{sin\rho +cos\phi }{sin\phi +cos\rho }=\frac{sin\rho +cos(90-(\theta +\rho ))}{sin(90-(\theta +\rho ))+cos\rho }=$$$$\frac{sin\rho +sin(\theta +\rho )}{cos(\theta +\rho )+cos\rho }=\frac{2sin(\rho +\frac{\theta }{2})cos\left(\frac{\theta }{2}\right)}{2cos(\rho +\frac{\theta }{2})cos\left(\frac{\theta }{2}\right)}=$$$$tan(\rho +\frac{\theta }{2})=k$$

Commented by HongKing last updated on 01/Feb/22

$$\mathrm{thank}\mathrm{you}\mathrm{dear}\mathrm{Sir}$$

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