Find the value of this expression (−1)(2^2 −1)+(((3^2 −2))/(2!)) − (((4^2 −3))/(3!)) + …+ (((2019^2 −2018))/(2018!))


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Question Number 165383 by naka3546 last updated on 01/Feb/22

$F i n d t h e v a l u e o f t h i s e x p r e s s i o n$ $(- 1) (2^{2} - 1) + \frac{(3^{2} - 2)}{2!} - \frac{(4^{2} - 3)}{3!} + \dots + \frac{(2019^{2} - 2018)}{2018!}$
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