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Question Number 165531 by ajfour last updated on 03/Feb/22

Commented by ajfour last updated on 03/Feb/22

$$ForclassXI,perhaps!$$

Answered by mr W last updated on 03/Feb/22

Commented by mr W last updated on 03/Feb/22

$$\tan \alpha =\frac{1}{a}$$$$FC=b(\sin \alpha +\frac{1}{\cos \alpha })=a\cos \alpha$$$$\frac{b}{a}=\frac{{\cos }^2\alpha }{1+\sin \alpha \cos \alpha }=\frac{a^2}{(1+a^2)(1+\frac{a}{1+a^2})}$$$$b=\frac{a^3}{a^2+a+1}$$

Commented by ajfour last updated on 03/Feb/22

$$verypleasant,Sir!$$

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