All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 165550 by mnjuly1970 last updated on 03/Feb/22
Answered by mahdipoor last updated on 03/Feb/22
f(1)=11,f(f(1))=22,f(f(f(1)))=33...f(f...f(1)...)=10n+1⇒f′(x)=xx2+10f′(1)×f(11)×f(22)×...×f(10n+1)=111×1122×2233×...×10n+110n+11=110n+11=1n+1⇒n2−8n−10=0⇒n=8±1042∉N⇒withuotanswerbutif110n+11=1n⇒n2−10n−11=0⇒n=11or−1⇒n=11
Terms of Service
Privacy Policy
Contact: info@tinkutara.com