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Question Number 165742 by amin96 last updated on 07/Feb/22

$$\mathit{p}\mathit{r}\mathit{o}\mathit{v}\mathit{e}\mathit{t}\mathit{h}\mathit{a}\mathit{t}$$$$\underset{\mathbf{n}=0}{\sum ^{\mathrm{\infty }}}\frac{\left(2\mathbf{n}\right)!}{{(\mathbf{n}!)}^2{4}^{\mathbf{n}}{(2\mathbf{n}+1)}^4}\stackrel{?}{=}\frac{\pi }{96}(12\mathit{\zeta }\left(3\right)+8{\mathbf{ln}}^3\left(2\right)+2{\pi }^2\mathbf{ln}\left(2\right))$$$$$$$$--------\mathit{b}\mathit{y}\mathit{M}.\mathit{A}$$

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