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Question Number 165804 by cortano1 last updated on 08/Feb/22

Answered by MJS_new last updated on 09/Feb/22

$$\left(1\right)y=-\frac{x(5x-1)}{3(x-1)}$$$$\Rightarrow$$$$\left(2\right)x^3-x^2=\frac{x^2{(5x-1)}^2(5x^2-1)}{9{(x-1)}^3}$$$$\Rightarrow x=0\wedge y=0★$$$$x^4-\frac{7}{58}{x}^3-\frac{37}{58}{x}^2+\frac{23}{58}x-\frac{5}{58}=0$$$$(x+1)(x-\frac{1}{2})(x^2-\frac{28}{29}x+\frac{5}{29})=0$$$$\Rightarrow$$$$x=-1\wedge y=1★$$$$x=y=\frac{1}{2}★$$$$x=\frac{9}{29}\pm \frac{8}{29}\mathrm{i}\wedge y=-\frac{16}{87}\pm \frac{6}{29}\mathrm{i}★$$$$★3\mathrm{real}\mathrm{\&}2\mathrm{complex}\mathrm{solutions}$$

Commented by Tawa11 last updated on 10/Feb/22

$$\mathrm{Weldone}\mathrm{sir}$$

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