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Question Number 165893 by Tawa11 last updated on 09/Feb/22

Commented by otchereabdullai@gmail.com last updated on 18/Feb/22

$$\mathrm{nice}$$

Answered by som(math1967) last updated on 10/Feb/22

$$Vol.ofhemisphericaltank=\frac{2}{3}\pi \times 5^3{m}^3$$$$vol.ofwaterfilledin1secfrom$$$$pipe=\pi \times {(0..2)}^2\times 2m^3$$$$timetakentofillthetank$$$$=\frac{2\times \pi \times 5^3}{3\times \pi \times {(0.2)}^2\times 2}=\frac{125}{.12}sec$$$$=17.4minute$$

Commented by Tawa11 last updated on 10/Feb/22

$$\mathrm{Thanks}\mathrm{sirs}.$$

Commented by Tawa11 last updated on 10/Feb/22

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by Tawa11 last updated on 10/Feb/22

$$\mathrm{Som}\mathrm{sir}.\mathrm{thanks}\mathrm{for}\mathrm{your}\mathrm{effort}.$$

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