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Question Number 166058 by cortano1 last updated on 12/Feb/22
Answered by som(math1967) last updated on 12/Feb/22
△ABC∼△ALB∼△CLBlet∡BAC=∡DCL=αAL×AC=a2AL=a2a2+b2LC×AC=b2LC=b2a2+b2from△ALBcosα=a2a2+b2×a=aa2+b2from△LCDcosα=LC2+a2−x22LCaaa2+b2=b4a2+b2+a2−x22b2aa2+b22a2b2a2+b2=b4+a4+a2b2a2+b2−x2x2=a4−a2b2+b4a2+b2=(a2+b2)(a4−a2b2+b4)(a2+b2)2x2=(a6+b6)(a2+b2)2∴x=a6+b6a2+b2
Commented by som(math1967) last updated on 12/Feb/22
Commented by Tawa11 last updated on 12/Feb/22
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