Question Number 16633 by tawa tawa last updated on 24/Jun/17
$$\sqrt{\mathrm{1}}\:.\:\sqrt{\mathrm{2}}\:.\:\sqrt{\mathrm{3}}.\:...\:\sqrt{\mathrm{n}}\:\:=\:\mathrm{S}_{\mathrm{n}} \\ $$$$\mathrm{what}\:\mathrm{is}\:\:\mathrm{S}_{\mathrm{n}} \:? \\ $$
Commented by Arnab Maiti last updated on 02/Jul/17
$$\mathrm{S}_{\mathrm{n}} =\sqrt{\mathrm{n}!} \\ $$