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Question Number 166424 by leicianocosta last updated on 20/Feb/22

Commented by cortano1 last updated on 20/Feb/22

$$\Rightarrow \mathrm{let}\mathrm{AB}=\mathrm{BC}=4$$$$\Rightarrow \mathrm{AC}=4\sqrt{2}\Rightarrow \sin 30°=\frac{\mathrm{CD}}{4\sqrt{2}}$$$$\Rightarrow \mathrm{CD}=2\sqrt{2}$$

Commented by som(math1967) last updated on 20/Feb/22

$$AB=4$$

Commented by cortano1 last updated on 20/Feb/22

$$\mathrm{owh}\mathrm{yes}$$

Answered by som(math1967) last updated on 20/Feb/22

$$\measuredangle \mathit{B}\mathit{A}\mathit{C}=45°\therefore \measuredangle B\mathit{C}\mathit{A}=90°-45°=45°$$$$\therefore \mathit{A}\mathit{C}=\sqrt{4^2+4^2}=4\sqrt{2}$$$$\frac{\mathit{C}\mathit{D}}{\mathit{A}\mathit{C}}=\sin 30$$$$\mathit{C}\mathit{D}=\frac{1}{2}\times 4\sqrt{2}=2\sqrt{2}$$$$\mathit{A})2\sqrt{2}$$$$\mathit{A})\mathit{c}\mathit{o}\mathit{r}\mathit{r}\mathit{e}\mathit{t}\mathit{o}$$

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