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Question Number 166491 by mathlove last updated on 21/Feb/22

Commented by cortano1 last updated on 21/Feb/22

  = (1/(16))x−(1/(64)) sin 4x +(1/(48)) sin^3 2x + c

$$\:\:=\:\frac{\mathrm{1}}{\mathrm{16}}\mathrm{x}−\frac{\mathrm{1}}{\mathrm{64}}\:\mathrm{sin}\:\mathrm{4x}\:+\frac{\mathrm{1}}{\mathrm{48}}\:\mathrm{sin}\:^{\mathrm{3}} \mathrm{2x}\:+\:\mathrm{c} \\ $$

Commented by mathlove last updated on 21/Feb/22

solve it?

$${solve}\:{it}? \\ $$

Commented by cortano1 last updated on 21/Feb/22

yes

$$\mathrm{yes} \\ $$

Commented by mathlove last updated on 21/Feb/22

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