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Question Number 166649 by kurt last updated on 24/Feb/22
Commented by greogoury55 last updated on 27/Feb/22
y′=limh→0f(x+h)−f(x)h=limh→0(x+h)n−xnh=limh→0∑nk=0C(n,k)xn−khk−xnh=limh→0(n1)xn−1h+(n2)xn−2h2+...+hnh=limh→0(n1)xn−1+(n2)xn−2h+...+hn−1=(n1)xn−1=nxn−1.
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