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Question Number 166676 by ajfour last updated on 24/Feb/22

Answered by ajfour last updated on 24/Feb/22

$$R\sin \theta +2r=R$$$$\sin \theta =\frac{r}{R-r}$$$$\Rightarrow Rr=(R-2r)(R-r)$$$$\Rightarrow R^2-4rR+2r^2=0$$$$\frac{R}{r}=2+\sqrt{2}$$

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