Question Number 16689 by Nayon last updated on 25/Jun/17 | ||
$${why}\:{any}\:{infinitely}\:{differentiable}\:{function}\:{is}\:{a}\:{power}\:{series}? \\ $$ | ||
Answered by prakash jain last updated on 25/Jun/17 | ||
$$\mathrm{Taylor}\:\mathrm{Series}\:\mathrm{for}\:\mathrm{class}\:\mathrm{C}^{\infty} . \\ $$ | ||