A particle of mass 0.25kg vibrates with a period of 2secs. If its greatest displacement is 0.4m. What is its maximum kinetic energy.


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Question Number 166929 by MathsFan last updated on 02/Mar/22

$A p a r t i c l e o f m a s s 0.25 k g v i b r a t e s$ $w i t h a p e r i o d o f 2 s e c s . I f i t s$ $g r e a t e s t d i s p l a c e m e n t i s 0.4 m . W h a t$ $i s i t s m a x i m u m k i n e t i c e n e r g y .$
	Answered by mr W last updated on 02/Mar/22

	$ω = \frac{2 π}{T}$ ${K E}_{m a x} = \frac{{m v}_{m a x}^{2}}{2}$ $= \frac{m {(ω s_{m a x})}^{2}}{2}$ $= \frac{m}{2} {(\frac{2 π s_{m a x}}{T})}^{2}$ $= \frac{0.25}{2} \times {(\frac{2 π \times 0.4}{2})}^{2} = 0.1974 J$
	Commented by MathsFan last updated on 02/Mar/22

	$t h a n k y o u c h a m p i o n$
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