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Question Number 166940 by cortano1 last updated on 03/Mar/22
Answered by som(math1967) last updated on 03/Mar/22
∫exx+exxex(1+xex)dxletxex=z⇒(xex+ex)dx=dz∫dzz(z+1)=∫dzz−∫dzz+1=ln∣z∣−ln∣z+1∣+c[z=xex]
Commented by peter frank last updated on 03/Mar/22
thanks
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