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Question Number 167058 by cortano1 last updated on 05/Mar/22

Answered by mr W last updated on 05/Mar/22

$${(\frac{2}{r}+\frac{1}{1}-\frac{1}{2})}^2=2(\frac{2}{r^2}+\frac{1}{1^2}+\frac{1}{2^2})$$$$\frac{1}{r}=\frac{9}{8}$$$$\Rightarrow r=\frac{8}{9}$$

Commented by cortano1 last updated on 05/Mar/22

$$\mathrm{Descartes}\mathrm{theorem}?$$

Commented by mr W last updated on 05/Mar/22

$$yes$$

Commented by Tawa11 last updated on 05/Mar/22

$$\mathrm{Great}\mathrm{sir}$$

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