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Question Number 167241 by mathlove last updated on 10/Mar/22

(b/(11))  is General fraction  and 0.3a^(−)   faind  (a−9b)=?

$$\frac{{b}}{\mathrm{11}}\:\:{is}\:{General}\:{fraction}\:\:{and}\:\mathrm{0}.\overline {\mathrm{3}{a}} \\ $$$${faind}\:\:\left({a}−\mathrm{9}{b}\right)=? \\ $$

Answered by mr W last updated on 10/Mar/22

(b/(11))=0.3a^(−)   100×(b/(11))=30+a+(b/(11))  9b=30+a  ⇒9b−a=30

$$\frac{{b}}{\mathrm{11}}=\mathrm{0}.\overline {\mathrm{3}{a}} \\ $$$$\mathrm{100}×\frac{{b}}{\mathrm{11}}=\mathrm{30}+{a}+\frac{{b}}{\mathrm{11}} \\ $$$$\mathrm{9}{b}=\mathrm{30}+{a} \\ $$$$\Rightarrow\mathrm{9}{b}−{a}=\mathrm{30} \\ $$

Answered by HeferH last updated on 10/Mar/22

 ((3a^(−) )/(99)) = (b/(11))    “3a” needs to be a multiple of 9 in order to   simplify.   ((36)/(99)) = (4/(11))   a = 6   b = 4   (6 − 9∙4) = (6 − 36) = −30      (Sorry if I′m wrong, I′m new doing this)

$$\:\frac{\overline {\mathrm{3}{a}}}{\mathrm{99}}\:=\:\frac{{b}}{\mathrm{11}}\: \\ $$$$\:``\mathrm{3}{a}''\:{needs}\:{to}\:{be}\:{a}\:{multiple}\:{of}\:\mathrm{9}\:{in}\:{order}\:{to} \\ $$$$\:{simplify}. \\ $$$$\:\frac{\mathrm{36}}{\mathrm{99}}\:=\:\frac{\mathrm{4}}{\mathrm{11}} \\ $$$$\:{a}\:=\:\mathrm{6} \\ $$$$\:{b}\:=\:\mathrm{4} \\ $$$$\:\left(\mathrm{6}\:−\:\mathrm{9}\centerdot\mathrm{4}\right)\:=\:\left(\mathrm{6}\:−\:\mathrm{36}\right)\:=\:−\mathrm{30} \\ $$$$\: \\ $$$$\:\left({Sorry}\:{if}\:{I}'{m}\:{wrong},\:{I}'{m}\:{new}\:{doing}\:{this}\right) \\ $$

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