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Question Number 167336 by mnjuly1970 last updated on 13/Mar/22

$$$$ $$0<x<\frac{\pi }{2}$$ $$f\left(x\right)=\sqrt[20]{sin\left(x\right)}+\sqrt[20]{cos\left(x\right)}$$ $$R_f=?\left(Range\right)$$ $$$$

Answered by MJS_new last updated on 13/Mar/22

$$0<f\left(x\right)<2^{39/40}$$

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