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Question Number 167339 by mnjuly1970 last updated on 13/Mar/22

Commented by Tawa11 last updated on 19/Mar/22

$$\mathrm{Great}\mathrm{sir}.$$

Answered by greogoury55 last updated on 13/Mar/22

$$r=\sqrt{7^2+4^2}=\sqrt{49+16}=\sqrt{65}$$$$x=\sqrt{4^2+r^2}=\sqrt{16+65}=\sqrt{81}=9$$

Answered by som(math1967) last updated on 13/Mar/22

$$Radiusofsemicircle=\sqrt{7^2+4^2}=\sqrt{65}$$$$\therefore x=\sqrt{65+16}=9$$

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