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Question Number 167380 by MathsFan last updated on 14/Mar/22

$$\mathit{s}\mathit{h}\mathit{o}\mathit{w}\mathit{t}\mathit{h}\mathit{a}\mathit{t}$$$${\mathit{A}}^{\prime }\cup {\mathit{B}}^{\prime }\cup {\mathit{C}}^{\prime }={(\mathit{A}\cup \mathit{B}\cup \mathit{C})}^{\prime }$$

Commented by cortano1 last updated on 15/Mar/22

$$\mathrm{wrong}$$

Commented by Rasheed.Sindhi last updated on 15/Mar/22

$${\mathit{A}}^{\prime }\cup {\mathit{B}}^{\prime }\cup {\mathit{C}}^{\prime }={(\mathit{A}\cap \mathit{B}\cap \mathit{C})}^{\prime }$$$$\mathrm{or}$$$${\mathit{A}}^{\prime }\cap {\mathit{B}}^{\prime }\cap {\mathit{C}}^{\prime }={(\mathit{A}\cup \mathit{B}\cup \mathit{C})}^{\prime }$$

Commented by MathsFan last updated on 15/Mar/22

$$ohisee$$$$thankyousir$$

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