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Question Number 167404 by bharath23 last updated on 15/Mar/22

Answered by alephzero last updated on 15/Mar/22

$$\frac{\partial f}{\partial x}=\frac{\partial }{\partial x}\left(y\cos xy\right)=y\frac{\partial }{\partial x}\left(\cos xy\right)$$$$=y\frac{\partial \left(\cos xy\right)}{\partial \left(xy\right)}\cdot \frac{\partial \left(xy\right)}{\partial x}=-y^2\sin xy◼$$

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