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Question Number 167419 by Bagus1003 last updated on 16/Mar/22
(12)!=?UseMethodandFormula!!!!!!!!!
Commented by mkam last updated on 16/Mar/22
(12)!=Γ(32)=12Γ(12)=π2
Answered by alephzero last updated on 16/Mar/22
n!=Γ(n+1)⇒(12)!=Γ(32)=Γ(1+12)Γ(n)Γ(n+12)=21−2nπΓ(2n)Γ(32)=Γ(1)Γ(1+12)=Γ(1+12)=21−2πΓ(2)=π2
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