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Question Number 167456 by Khalmohmmad last updated on 17/Mar/22

Answered by MJS_new last updated on 17/Mar/22

$$\tan 760\ne 4$$$$\tan 76°\ne 4$$$$\sin 14\approx .990607$$$$\sin 14°\approx .241922$$$${\sin }^{2}14\approx .981303$$$${\sin }^{2}14°\approx .0585262$$$$$$$$\mathrm{for}\alpha \mathrm{in}\mathrm{degree}:$$$$\tan \alpha =t\Rightarrow {\sin }^2(90-\alpha )=\frac{1}{t^2+1}$$$$\mathrm{so}\mathrm{if}\tan \alpha =4\Rightarrow {\sin }^2(90-\alpha )=\frac{1}{17}$$

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